X2 10x 21 0

$$ f(x) = x^2 + 10x + 21 $$ $$ a=1,b=10 $$ Result: $$ X = −b / 2a $$ Now, equation of axis of symmetry calculator with steps substitute the values in standard equation $$ x = −(10) / 2(1) $$ $$ x = −10 / 2 $$ $$ x = −5 / 1 $$ $$ x = − 5 $$ Derive the Axis of Symmetry for Parabola: The equation for axis of symmetry for a parabola is

Algebra. Solve by Factoring x^2-10x=0. x2 − 10x = 0 x 2 - 10 x = 0. Factor x x out of x2 −10x x 2 - 10 x. Tap for more steps... x(x−10) = 0 x ( x - 10) = 0. If any individual factor on the left side of the equation is equal to 0 0, the entire expression will be equal to 0 0. x = 0 x = 0. x−10 = 0 x - 10 = 0.y = x2 - 10x + 21. Find the properties of the given parabola. Tap for more steps... Direction: Opens Up. Vertex: (5, - 4) Focus: (5, - 15 4) Axis of Symmetry: x = 5. Directrix: y = - 17 4. Select a few x values, and plug them into the equation to find the corresponding y values.x2 − 10x − 21 = 0. https://www.tiger-algebra.com/drill/x~2-10x-21=0/. x2-10x-21=0 Two solutions were found : x = (10-√184)/2=5-√ 46 = -1.782 x = (10+√184)/2=5+√ 46 = 11.782 Step by step solution : Step 1 :Trying to factor by splitting the middle term ... More Items.Algebra. Solve by Completing the Square x^2-10x+22=0. x2 − 10x + 22 = 0 x 2 - 10 x + 22 = 0. Subtract 22 22 from both sides of the equation. x2 − 10x = −22 x 2 - 10 x = - 22. To create a trinomial square on the left side of the equation, find a value that is equal to the square of half of b b. (b 2)2 = (−5)2 ( b 2) 2 = ( - 5) 2.x2-10x+25=9 Two solutions were found : x = 8 x = 2 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : ... 2x2-10x+5=0 Two solutions were found : x = (10-√60)/4= (5-√ 15 )/2= 0.564 x = (10+√60)/4= (5+√ 15 )/2= 4.436 Step by step solution : Step 1 :Equation at the end ...x2+10x+16=0 Two solutions were found : x = -2 x = -8 Step by step solution : Step 1 :Trying to factor by splitting the middle term 1.1 Factoring x2+10x+16 The first term is, x2 its ...To make the equation x^2 - 10x = 21 a perfect-square trinomial, we can add a certain value to both sides of the equation. The goal is to complete the square on the left side of the equation. Usually, to complete the square for an equation in the form of x^2 - bx = c, we add (b/2)^2 to both sides.

Solution See steps Quadratic equations Step by Step Solution Step by step solution : Step 1 : Trying to factor by splitting the middle term 1.1 Factoring x2-10x-21 The first term is, x2 its coefficient is 1 . The middle term is, -10x its coefficient is -10 . The last term, "the constant", is -21x^{2}-10x+21=0 . Add 14 and 7 to get 21. a+b=-10 ab=1\times 21=21 . To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as x^{2}+ax+bx+21. To find a and b, set up a system to be solved.-1,-21 -3,-7 . Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both ...Nov 18, 2014 · report flag outlined. Factorizar: x² + 10x + 21 Trinomio de la forma x² +bx +c. Sacamos √x² = x . La colocamos en ambos patentesis. (x ) ( x ) Bajamos el signo del segundo termino. (x + ) ( x ) Multiplicamos el signo del 2do termino y el 3er termino + por + = +; lo bajamos. Dec 18, 2020 · X2 + 10x + 21 = 0 factorizacion porfa Ver respuesta Publicidad Publicidad babschvp9gmnn babschvp9gmnn Respuesta: (x+3)((x+7) Explicación paso a paso: 2.2 Solving -x2+10x+22 = 0 by Completing The Square . Multiply both sides of the equation by (-1) to obtain positive coefficient for the first term: x2-10x-22 = 0 Add 22 to both side of the equation : x2-10x = 22. Now the clever bit: Take the coefficient of x , which is 10 , divide by two, giving 5 , and finally square it giving 25.Apr 7, 2022 · Step-by-step explanation: Completing the square means you are changing the polynomial so that it is a perfect square trinomial. Since the middle term is 10, we need the last term to be 25 since 5+5=10, thus, 5*5=25: As you can see, because we change to by adding 4 to both sides, we were able to reduce it to , a perfect square, and solve the ...

3.2 Solving x 2-10x+21 = 0 by Completing The Square . Subtract 21 from both side of the equation : x 2-10x = -21 Now the clever bit: Take the coefficient of x , which is 10 , divide by two, giving 5 , and finally square it giving 25 Add 25 to both sides of the equation : On the right hand side we have : -21 + 25 or, (-21/1)+(25/1) amathzing. comment. 1. To factor a trinomial in the form Ax^2 + Bx + C when the A = 1. You need to find the factors of C that when added or subtracted will give you B. Factors of 21 are either 1,21 or 3,7. Since +3 and +7 will give you 10 then those will be the two factors you will use. Factoring x^2+10x+21 will give you (x+3) (x+7)x^{2}-10x+21=0 . Add 14 and 7 to get 21. a+b=-10 ab=1\times 21=21 . To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as x^{2}+ax+bx+21. To find a and b, set up a system to be solved.-1,-21 -3,-7 . Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both ...Solve x2 + 12x = -20 by completing the square. Add to both sides of the equation. The value of in this equation is . Write the left side of the equation as a binomial squared. The left side of the equation becomes ()2. Use the square root property of equality. Solve x2 + 8x = 33 by completing the square.Precalculus. Find the Vertex Form y=x^2-10x+21. y = x2 − 10x + 21 y = x 2 - 10 x + 21. Complete the square for x2 −10x+21 x 2 - 10 x + 21. Tap for more steps... (x−5)2 −4 ( x - 5) 2 - 4. Set y y equal to the new right side. y = (x− 5)2 −4 y = ( x - 5) 2 - 4.

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4.2 Solving x 2 +10x+21 = 0 by Completing The Square . Subtract 21 from both side of the equation : x 2 +10x = -21 Now the clever bit: Take the coefficient of x , which is 10 , divide by two, giving 5 , and finally square it giving 25 Add 25 to both sides of the equation : On the right hand side we have : -21 + 25 or, (-21/1)+(25/1)3.2 Solving x 2 +10x+21 = 0 by Completing The Square . Subtract 21 from both side of the equation : x 2 +10x = -21 Now the clever bit: Take the coefficient of x , which is 10 , divide by two, giving 5 , and finally square it giving 25 Add 25 to both sides of the equation : On the right hand side we have :4.2 Solving x2+10x+21 = 0 by Completing The Square . Subtract 21 from both side of the equation : x2+10x = -21. Now the clever bit: Take the coefficient of x , which is 10 , divide by two, giving 5 , and finally square it giving 25. Add 25 to both sides of the equation : On the right hand side we have :Algebra. Find the Vertex f (x)=x^2-10x+16. f (x) = x2 − 10x + 16 f ( x) = x 2 - 10 x + 16. Rewrite the equation in vertex form. Tap for more steps... y = (x− 5)2 −9 y = ( x - 5) 2 - 9. Use the vertex form, y = a(x−h)2 +k y = a ( x - h) 2 + k, to determine the values of a a, h h, and k k. a = 1 a = 1. h = 5 h = 5.Answer Question. Answer (1 of 2): X^2-10x=-21It is a quadratic equation with variable x. x2 - 10x = -21adding 21 on both sidesx2 - 10x + 21 = -21 + 21x2 - 10x + 21 = 0x2 - 7x - 3x + 21 0x (x - 7) - 3 (x - 7) = 0 (x - 3) (x - 7) = 0x-3 = 0; x - 7 =0x = 3, 7So, the values of x are 3 and .

f (x) = x2 − 10x + 21 f ( x) = x 2 - 10 x + 21. Find the properties of the given parabola. Tap for more steps... Direction: Opens Up. Vertex: (5,−4) ( 5, - 4) Focus: (5,−15 4) ( 5, - 15 4) Axis of Symmetry: x = 5 x = 5. Directrix: y = −17 4 y = - 17 4. Select a few x x values, and plug them into the equation to find the corresponding y ...Aug 9, 2023 · To convert a parabola from vertex to standard form: Write down the parabola equation in the vertex form: y = a (x-h)² + k. Expand the expression in the bracket: y = a (x² - 2hx + h²) + k. Multiply the terms in the parenthesis by a: y = ax² - 2ahx + ah² + k. Compare the outcome with the standard form of a parabola: y = ax² + bx + c. x2-10x-3000=0 Two solutions were found : x = 60 x = -50 Step by step solution : Step 1 :Trying to factor by splitting the middle term 1.1 Factoring x2-10x-3000 The first term is, ...Solve by Completing the Square x^2+10x-1=0. x2 + 10x − 1 = 0 x 2 + 10 x - 1 = 0. Add 1 1 to both sides of the equation. x2 + 10x = 1 x 2 + 10 x = 1. To create a trinomial square on the left side of the equation, find a value that is equal to the square of half of b b. (b 2)2 = (5)2 ( b 2) 2 = ( 5) 2. Add the term to each side of the equation.4.2 Solving x 2 +10x+21 = 0 by Completing The Square . Subtract 21 from both side of the equation : x 2 +10x = -21 Now the clever bit: Take the coefficient of x , which is 10 , divide by two, giving 5 , and finally square it giving 25 Add 25 to both sides of the equation : On the right hand side we have : -21 + 25 or, (-21/1)+(25/1)Algebra Factor x^2-10x+21 x2 − 10x + 21 x 2 - 10 x + 21 Consider the form x2 + bx+c x 2 + b x + c. Find a pair of integers whose product is c c and whose sum is b b. In this case, whose product is 21 21 and whose sum is −10 - 10. −7,−3 - 7, - 3 Write the factored form using these integers. (x−7)(x− 3) ( x - 7) ( x - 3)Algebra Solve Using the Quadratic Formula x^2-10x+21=0 x2 − 10x + 21 = 0 x 2 - 10 x + 21 = 0 Use the quadratic formula to find the solutions. −b±√b2 −4(ac) 2a - b ± b 2 - 4 ( a c) 2 a Substitute the values a = 1 a = 1, b = −10 b = - 10, and c = 21 c = 21 into the quadratic formula and solve for x x.Algebra. Find the Vertex f (x)=x^2-10x+16. f (x) = x2 − 10x + 16 f ( x) = x 2 - 10 x + 16. Rewrite the equation in vertex form. Tap for more steps... y = (x− 5)2 −9 y = ( x - 5) 2 - 9. Use the vertex form, y = a(x−h)2 +k y = a ( x - h) 2 + k, to determine the values of a a, h h, and k k. a = 1 a = 1. h = 5 h = 5.To factor −5x2 + 10x, we can factor out the greatest common factor, which is −5x, giving us −5x(x + 2). Explanation: To factor −5x2 + 10x, we can first factor out the greatest common factor, which is −5x. This gives us −5x(x + 2). Therefore, the correct factorization is −5x(x + 2). Learn more about Factoring here:x 2 + 10x + 21 = 0 has two solutions: x = -5 + √ 4 or x = -5 - √ 4 . Solve Quadratic Equation using the Quadratic Formula 3.3 Solving x 2 +10x+21 = 0 by the Quadratic Formula . According to the Quadratic Formula, x , the solution for Ax 2 +Bx+C = 0 , where A, B and C are numbers, often called coefficients, is given by :

Find the roots of the equation √3 x^2 + 10x – 8√3 = 0 if they exist, by applying the quadratic formula. asked Apr 14, 2020 in Quadratic Equations by Vevek01 ( 47.4k points) quadratic equations

x2+10x+16=0 Two solutions were found : x = -2 x = -8 Step by step solution : Step 1 :Trying to factor by splitting the middle term 1.1 Factoring x2+10x+16 The first term is, x2 its ...Álgebra. Resuelva por factorización x^2+10x+21=0. x2 + 10x + 21 = 0 x 2 + 10 x + 21 = 0. Factoriza x2 +10x+21 x 2 + 10 x + 21 con el método AC. Toca para ver más pasos... (x+3)(x+ 7) = 0 ( x + 3) ( x + 7) = 0. Si cualquier factor individual en el lado izquierdo de la ecuación es igual a 0 0, la expresión completa será igual a 0 0.#rArr x^2 - 10x + 25 = 21 + 25 # # rArr (x - 5 )^2 = 46 # There is now a perfect square on the left side . Answer link. Related questions.Jul 21, 2022 at 16:36 $\begingroup$ It's have been a octet in general which may or may not have but easy to solve. As Robert Z showed this specifically designed to give us the dicriminant $\sqrt{b^2 -4ac} = \sqrt{100 - 4(25 \pm foo)}= \sqrt{\pm 4foo}$ which as it must be positive $2\sqrt{foo}$ so the whole thing always collapses. $\endgroup$Algebra. Find the Roots (Zeros) f (x)=x^2-10x+25. f (x) = x2 − 10x + 25 f ( x) = x 2 - 10 x + 25. Set x2 −10x+ 25 x 2 - 10 x + 25 equal to 0 0. x2 − 10x+25 = 0 x 2 - 10 x + 25 = 0. Solve for x x. Tap for more steps... x = 5 x = 5. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework ...3.2 Solving x 2 +10x+21 = 0 by Completing The Square . Subtract 21 from both side of the equation : x 2 +10x = -21 Now the clever bit: Take the coefficient of x , which is 10 , divide by two, giving 5 , and finally square it giving 25 Add 25 to both sides of the equation : On the right hand side we have : -21 + 25 or, (-21/1)+(25/1)Solve by Completing the Square x^2-10x-4=0. x2 − 10x − 4 = 0 x 2 - 10 x - 4 = 0. Add 4 4 to both sides of the equation. x2 − 10x = 4 x 2 - 10 x = 4. To create a trinomial square on the left side of the equation, find a value that is equal to the square of half of b b. (b 2)2 = (−5)2 ( b 2) 2 = ( - 5) 2. Add the term to each side of the ...`x^2 - 10x + 21 = 0` Advertisement. Solution Show Solution `x^2 - 10x + 21 = 0` Here a = 1, b = - 10 and c = 21. Then `x = (-b +- sqrt(b^2 - 4ac))/(2a)`

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Solve by Completing the Square x^2-10x+10=0. Step 1. Subtract from both sides of the equation. Step 2. To create a trinomial square on the left side of the equation, find a value that is equal to the square of half of . Step 3. Add the term to each side of the equation. Step 4. Simplify the equation.Solution for x^2+10x+21=0. A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y.Solve Quadratic Equation by Completing The Square. 4.2 Solving x2-10x+21 = 0 by Completing The Square . Subtract 21 from both side of the equation : x2-10x = -21. Now the clever bit: Take the coefficient of x , which is 10 , divide by two, giving 5 , and finally square it giving 25. Add 25 to both sides of the equation :Step-by-step explanation: Completing the square means you are changing the polynomial so that it is a perfect square trinomial. Since the middle term is 10, we need the last term to be 25 since 5+5=10, thus, 5*5=25: As you can see, because we change to by adding 4 to both sides, we were able to reduce it to , a perfect square, and solve the ...Algebra. Factor x^2-10x-24. x2 − 10x − 24 x 2 - 10 x - 24. Consider the form x2 + bx+c x 2 + b x + c. Find a pair of integers whose product is c c and whose sum is b b. In this case, whose product is −24 - 24 and whose sum is −10 - 10. −12,2 - 12, 2. Write the factored form using these integers. (x−12)(x +2) ( x - 12) ( x + 2)Dimitri is solving the equation x2 – 10x = 21. Which value must be added to both sides of the equation to make the left side a perfect-square trinomial? 0 4 25 100. loading. See answers. Ask AI. loading. report flag outlined. loading. bell outlined. Log in to add comment. Advertisement. AI-generated answer. Answer. 7 people found it helpful.Solve your math problems using our free math solver with step-by-step solutions. Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more.x 2 + 10x + 21 = 0 has two solutions: x = -5 + √ 4 or x = -5 - √ 4 . Solve Quadratic Equation using the Quadratic Formula 4.3 Solving x 2 +10x+21 = 0 by the Quadratic Formula . According to the Quadratic Formula, x , the solution for Ax 2 +Bx+C = 0 , where A, B and C are numbers, often called coefficients, is given by :12 thg 12, 2021 ... Akar-akar yang memenuhi persamaan kuadrat x²−10x+21=0 adalah .... a. −7 dan −3 b. −7 dan 3 c. 3 dan7 d. 3 dan 10.y = x2 - 10x + 21. Find the properties of the given parabola. Tap for more steps... Direction: Opens Up. Vertex: (5, - 4) Focus: (5, - 15 4) Axis of Symmetry: x = 5. Directrix: y = - 17 4. Select a few x values, and plug them into the equation to find the corresponding y values.To make things easier, you can take the factor −1 out: Explanation: = −1⋅(x2 −11x−26) Now we factor −26 = −13⋅2 ... -x2+10x-21=0 Two solutions were found : x = 7 x = 3 Step by step solution : Step 1 : Step 2 :Pulling out like terms : 2.1 Pull out like factors : -x2 + 10x - 21 = -1 • (x2 - ... -x2+10x-24=0 Two solutions were ...Solve Factor (x − 7) (x − 3) Solution Steps Steps Using the Quadratic Formula Steps Using Direct Factoring Method View solution steps Evaluate (x − 7) (x − 3) Graph Quiz … ….

Popular Problems Algebra Solve by Factoring x^2-10x=-21 x2 − 10x = −21 x 2 - 10 x = - 21 Add 21 21 to both sides of the equation. x2 − 10x+21 = 0 x 2 - 10 x + 21 = 0 Factor x2 − …Find step-by-step Algebra solutions and your answer to the following textbook question: Which expression is the factorization of x^2 + 10x + 21? a. (x + 3)(x + 7) b.Álgebra. Resuelva por factorización x^2+10x+21=0. x2 + 10x + 21 = 0 x 2 + 10 x + 21 = 0. Factoriza x2 +10x+21 x 2 + 10 x + 21 con el método AC. Toca para ver más pasos... (x+3)(x+ 7) = 0 ( x + 3) ( x + 7) = 0. Si cualquier factor individual en el lado izquierdo de la ecuación es igual a 0 0, la expresión completa será igual a 0 0.`x^2 - 10x + 21 = 0` Advertisement. Solution Show Solution `x^2 - 10x + 21 = 0` Here a = 1, b = - 10 and c = 21. Then `x = (-b +- sqrt(b^2 - 4ac))/(2a)`Dimitri is solving the equation x2 – 10x = 21. Which value must be added to both sides of the equation to make the left side a perfect-square trinomial? 0 4 25 100. loading. See answers. Ask AI. loading. report flag outlined. loading. bell outlined. Log in to add comment. Advertisement. AI-generated answer. Answer. 7 people found it helpful.r = 4 Explanation: x2 +y2 +Dx+Ey+F = 0 C (a,b) coordinates for center of circle a =− 2D b = − 2E F = 21 ... x2+y2-10x-8y+37=0 No solutions found Step by step solution : Step 1 :Equation at the end of step 1 : x2 - 10x + y2 - 8y + 37 = …Tiger shows you, step by step, how to solve YOUR Quadratic Equations x^2+10x+21=0 by Completing the Square, Quadratic formula or, whenever possible, by Factoring Home …So you'd set the first set of parentheses like so: (x-2)=0. Then to isolate "x", you would add 2 to both sides to get x=2. Then, You would set the other set of parentheses to zero, like so: (x+4)=0. To isolate "x", you would subtract 4 from both sides to get x=-4. So, your final answer would be x=2 or x=-4. Hope this helped you out.To make the equation x^2 - 10x = 21 a perfect-square trinomial, we can add a certain value to both sides of the equation. The goal is to complete the square on the left side of the equation. Usually, to complete the square for an equation in the form of x^2 - bx = c, we add (b/2)^2 to both sides. X2 10x 21 0, [text-1-1], [text-1-1], [text-1-1], [text-1-1], [text-1-1], [text-1-1], [text-1-1], [text-1-1], [text-1-1], [text-1-1], [text-1-1], [text-1-1], [text-1-1], [text-1-1], [text-1-1], [text-1-1], [text-1-1], [text-1-1], [text-1-1], [text-1-1], [text-1-1], [text-1-1], [text-1-1], [text-1-1], [text-1-1], [text-1-1], [text-1-1], [text-1-1], [text-1-1], [text-1-1], [text-1-1], [text-1-1], [text-1-1]